Home
Class 11
PHYSICS
Two spherical soap bubbles of radii r(1)...

Two spherical soap bubbles of radii `r_(1) and r_(2)` in vaccum coalesce under isothermal conditions. The resulting bubble has a radius R such that

A

`(r_(1) + r_(2))//2`

B

`R = [r_(1)r_(2)]//r_(1) + r+(2)`

C

`R = sqrt((r_(1)^(2) + r_(2)^(2)))`

D

`R = r_(1) + r_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of two spherical soap bubbles coalescing under isothermal conditions, we will derive the formula for the radius \( R \) of the resulting bubble from the radii \( r_1 \) and \( r_2 \) of the original bubbles. ### Step-by-Step Solution: 1. **Understanding the Problem**: - We have two soap bubbles with radii \( r_1 \) and \( r_2 \). - When these bubbles coalesce, they form a new bubble with radius \( R \). - The process occurs under isothermal conditions, meaning the temperature remains constant. 2. **Pressure Inside the Bubbles**: - The pressure inside a soap bubble is given by the formula: \[ P = \frac{4S}{R} \] where \( S \) is the surface tension of the soap solution and \( R \) is the radius of the bubble. - Therefore, the pressures inside the two bubbles are: \[ P_1 = \frac{4S}{r_1} \quad \text{and} \quad P_2 = \frac{4S}{r_2} \] 3. **Volume of the Bubbles**: - The volume \( V \) of a sphere is given by: \[ V = \frac{4}{3} \pi R^3 \] - Hence, the volumes of the two bubbles are: \[ V_1 = \frac{4}{3} \pi r_1^3 \quad \text{and} \quad V_2 = \frac{4}{3} \pi r_2^3 \] 4. **Using the Isothermal Condition**: - Under isothermal conditions, the total pressure-volume product before coalescence equals that after coalescence: \[ P_1 V_1 + P_2 V_2 = P R^3 \] - Substituting the expressions for pressure and volume: \[ \left(\frac{4S}{r_1}\right) \left(\frac{4}{3} \pi r_1^3\right) + \left(\frac{4S}{r_2}\right) \left(\frac{4}{3} \pi r_2^3\right) = \left(\frac{4S}{R}\right) \left(\frac{4}{3} \pi R^3\right) \] 5. **Simplifying the Equation**: - Cancel out common factors (\( 4S \) and \( \frac{4}{3} \pi \)): \[ \frac{r_1^2}{R} + \frac{r_2^2}{R} = R^2 \] - Rearranging gives: \[ R^2 = \frac{r_1^2 + r_2^2}{R} \] - Multiplying through by \( R \): \[ R^3 = r_1^2 + r_2^2 \] 6. **Finding the Radius of the New Bubble**: - Therefore, the radius \( R \) of the new bubble is: \[ R = \sqrt{r_1^2 + r_2^2} \] ### Final Result: The radius \( R \) of the resulting bubble after coalescence is given by: \[ R = \sqrt{r_1^2 + r_2^2} \]

To solve the problem of two spherical soap bubbles coalescing under isothermal conditions, we will derive the formula for the radius \( R \) of the resulting bubble from the radii \( r_1 \) and \( r_2 \) of the original bubbles. ### Step-by-Step Solution: 1. **Understanding the Problem**: - We have two soap bubbles with radii \( r_1 \) and \( r_2 \). - When these bubbles coalesce, they form a new bubble with radius \( R \). - The process occurs under isothermal conditions, meaning the temperature remains constant. ...
Promotional Banner

Topper's Solved these Questions

  • COMPETITION CARE UNIT

    ICSE|Exercise PROPERTIES OF MATTER (CALORIMETRY, CHANGE OF STATE & KINETIC THEORY OF GASES ) |30 Videos
  • COMPETITION CARE UNIT

    ICSE|Exercise INTERNAL ENERGY |40 Videos
  • COMPETITION CARE UNIT

    ICSE|Exercise PROPERTIES OF MATTER (ELASTICITY ) |22 Videos
  • CIRCULAR MOTION

    ICSE|Exercise MODULE 2 (FROM ROTATIONAL KINETIC ENERGY , WORK ,POWER)|24 Videos
  • DIMENSIONS

    ICSE|Exercise SELECTED PROBLEMS (FROM CONVERSIONS OF ONE SYSTEMS OF UNITS INTO ANOTHER)|9 Videos

Similar Questions

Explore conceptually related problems

Two spherical soap bubbles of radii a and b in vacuum coalesce under isothermal conditions. The resulting bubble has a radius given by

Two soap bubbles having radii 3 cm and 4 cm in vacuum, coalesce under isothermal conditions. The radius of the new bubble is

Two soap bubbles one of radius 3cm and other of radius 4cm each coaless in vacuum under isothermal conditons. Calculate the radius of the bubble formed ?

Under isothermal condition two soap bubbles of radii r_(1) and r_(2) coalesce to form a single bubble of radius r. The external pressure is p_(0) . Find the surface tension of the soap in terms of the given parameters.

The radii of two soap bubbles are r_(i) and r_(2) . In isothermal conditions, two meet together in vacuum. Then the radius kof the resultant bubble is given by

A soap bubble in vacuum has a radius of 3 cm ad another soap bubble in vacuum has a radius of 4 cm. if the two bubbles coalesce under isothermal condition, then the radius of the new bubble is

Two drops of equal radius r coalesce to form a single drop under isothermal conditions . The radius of such a drop would be

Prove that if two bubbles of radii r_(1) and r_(2) coalesce isothermally in vacuum then the radius of new bubble will be r=sqrt(r_(1)^(2)+r_(2)^(2))

The radius R of the soap bubble is doubled under isothermal condition. If T be the surface tension of soap bubble. The work done in doing so it given by

A soap bubble of radius R has formed at normal temperature and pressure under isothermal conditions. Complete the work done. The surface tension of soap solution is T .

ICSE-COMPETITION CARE UNIT-PROPERTIES OF MATTER (SURFACE TENSION )
  1. The work done to blow a scap bubble of radius. R (surface tension T)

    Text Solution

    |

  2. A drop of oil is placed on the surface of water. Which of the followin...

    Text Solution

    |

  3. At critical temperature, the surface tension of a liquid

    Text Solution

    |

  4. Two spherical soap bubbles of radii r(1) and r(2) in vaccum coalesce u...

    Text Solution

    |

  5. Energy needed in breaking a drop of radius R into n drops of radius r,...

    Text Solution

    |

  6. There is a horizontal film of soap solution. On it a thread is placed ...

    Text Solution

    |

  7. Soap helps in cleaning the clothes because

    Text Solution

    |

  8. When two capillary tubes of different diameters are dipped vertically,...

    Text Solution

    |

  9. Workdone to blow a bubble of volume V is W. The workdone is blowing a ...

    Text Solution

    |

  10. The work done is increasing the size of a soap film from 10 cm xx 6 cm...

    Text Solution

    |

  11. An incompressible fluid flows steadily through a cylinder pipe whic...

    Text Solution

    |

  12. By inserting a capillary tube into a depht l in water, the water rises...

    Text Solution

    |

  13. Water rises to a height 0f 10 cm in a capillary tube, and mercuryfalls...

    Text Solution

    |

  14. A square wire fram of size L is dipped in a liquid. On taking out a me...

    Text Solution

    |

  15. In a surface tension experiment with capillary tube water rises upto 0...

    Text Solution

    |

  16. Two unequal soap bubbles are formed one on each side of a tube closed ...

    Text Solution

    |

  17. The radii of two soap bubbles are r(1) and r(2) (r(2) lt r(1)). They m...

    Text Solution

    |

  18. Two capillary tubes of radii 0.2 cm and 0.4 cm are dipped in the same ...

    Text Solution

    |

  19. The work done to get 'n' smaller equal size spherical drop from a bigg...

    Text Solution

    |

  20. A 10 cm long wire is placed horizontal on the surface of water and is ...

    Text Solution

    |