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The radii of two soap bubbles are r(1) a...

The radii of two soap bubbles are `r_(1) and r_(2) (r_(2) lt r_(1))`. They meet to produce a double bubble. The radius of their common interface is

A

`(r_(1)r_(2))/(r_(1) + r_(2))`

B

`(r_(1) + r_(2))/ (2)`

C

`(r_(1)r_(2))/(r_(1)-r_(2))`

D

`r_(2)-r_(1)`

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The correct Answer is:
To find the radius of the common interface of two soap bubbles with radii \( r_1 \) and \( r_2 \) (where \( r_2 < r_1 \)), we can follow these steps: ### Step 1: Understand the Pressure Difference in Soap Bubbles The excess pressure inside a soap bubble is given by the formula: \[ \Delta P = P_{\text{inside}} - P_{\text{outside}} = \frac{4T}{R} \] where \( T \) is the surface tension of the soap solution and \( R \) is the radius of the bubble. ### Step 2: Set Up the Equations for Each Bubble For bubble 1 with radius \( r_1 \): \[ P_1 - P_0 = \frac{4T}{r_1} \quad \text{(1)} \] For bubble 2 with radius \( r_2 \): \[ P_2 - P_0 = \frac{4T}{r_2} \quad \text{(2)} \] Here, \( P_0 \) is the external pressure. ### Step 3: Set Up the Equation for the Common Interface For the common interface of the double bubble, the excess pressure difference is: \[ P_2 - P_1 = \frac{4T}{r} \] where \( r \) is the radius of the common interface. ### Step 4: Substitute the Pressures from Equations (1) and (2) Substituting \( P_1 \) and \( P_2 \) from equations (1) and (2): \[ \left( P_0 + \frac{4T}{r_2} \right) - \left( P_0 + \frac{4T}{r_1} \right) = \frac{4T}{r} \] This simplifies to: \[ \frac{4T}{r_2} - \frac{4T}{r_1} = \frac{4T}{r} \] ### Step 5: Simplify the Equation Dividing through by \( 4T \) (assuming \( T \neq 0 \)): \[ \frac{1}{r_2} - \frac{1}{r_1} = \frac{1}{r} \] ### Step 6: Rearranging the Equation Rearranging gives us: \[ \frac{1}{r} = \frac{1}{r_1} - \frac{1}{r_2} \] ### Step 7: Finding the Radius of the Common Interface Taking the reciprocal of both sides, we find: \[ r = \frac{r_1 r_2}{r_1 - r_2} \] ### Final Answer Thus, the radius of the common interface of the double bubble is: \[ r = \frac{r_1 r_2}{r_1 - r_2} \] ---

To find the radius of the common interface of two soap bubbles with radii \( r_1 \) and \( r_2 \) (where \( r_2 < r_1 \)), we can follow these steps: ### Step 1: Understand the Pressure Difference in Soap Bubbles The excess pressure inside a soap bubble is given by the formula: \[ \Delta P = P_{\text{inside}} - P_{\text{outside}} = \frac{4T}{R} \] where \( T \) is the surface tension of the soap solution and \( R \) is the radius of the bubble. ...
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ICSE-COMPETITION CARE UNIT-PROPERTIES OF MATTER (SURFACE TENSION )
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  2. A drop of oil is placed on the surface of water. Which of the followin...

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  3. At critical temperature, the surface tension of a liquid

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  4. Two spherical soap bubbles of radii r(1) and r(2) in vaccum coalesce u...

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  5. Energy needed in breaking a drop of radius R into n drops of radius r,...

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  6. There is a horizontal film of soap solution. On it a thread is placed ...

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  7. Soap helps in cleaning the clothes because

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  8. When two capillary tubes of different diameters are dipped vertically,...

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  9. Workdone to blow a bubble of volume V is W. The workdone is blowing a ...

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  10. The work done is increasing the size of a soap film from 10 cm xx 6 cm...

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  11. An incompressible fluid flows steadily through a cylinder pipe whic...

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  12. By inserting a capillary tube into a depht l in water, the water rises...

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  13. Water rises to a height 0f 10 cm in a capillary tube, and mercuryfalls...

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  14. A square wire fram of size L is dipped in a liquid. On taking out a me...

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  15. In a surface tension experiment with capillary tube water rises upto 0...

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  16. Two unequal soap bubbles are formed one on each side of a tube closed ...

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  17. The radii of two soap bubbles are r(1) and r(2) (r(2) lt r(1)). They m...

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  18. Two capillary tubes of radii 0.2 cm and 0.4 cm are dipped in the same ...

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  19. The work done to get 'n' smaller equal size spherical drop from a bigg...

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  20. A 10 cm long wire is placed horizontal on the surface of water and is ...

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