A gas at pressure `p_(0)` is contained in a vessel. If the masses of all the molecules are halved and their speeds doubled, the resulting pressure would be

Options

A. `4P_(0)`
B. `2P_(0)`
C. `P_(0)`
D. `P_(0)//2`

Answer

B

Explanation

`P_(0) = mn//3V [v_(1)^(2) + v_(2)^(2) + …. + v_(n)^(2)]`
`P = (1//3) (m//2) (n//v) [(2v_(1))^(2) + …. + (2v_(n)^(2))] = 2P_(0)`