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If one mole of a monoatomic gas (gamma=5...

If one mole of a monoatomic gas `(gamma=5//3)` is mixed with one mole of a diatomic gas `(gamma=7//5)`, the value `gamma` for the mixture is

A

`1.40`

B

`1.50`

C

`1.53`

D

`3.07`

Text Solution

Verified by Experts

The correct Answer is:
C
`gamma = n_(1)gamma_(1) + n_(2)//n_(1) + n_(2)`
` = [1 xx (5//3) + 1 xx (7//5) //2 = 1.53`
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