A Carnot engine has an efficiency of `1//6`. When the temperature of the sink is reduced by `62^(@)C`, its efficiency is doubled. The temperature of the source and the sink are, respectively.

Options

A. `95^(@)C, 37^(@)C`
B. `80^(@)C, 37^(@)C `
C. `99^(@)C, 37^(@)C `
D. `90^(@)C, 37^(@)C `

Answer

C

Explanation

`(1//6) - (T_(1)-T_(2))//T_(1), 2//6 - T_(1)-(T_(2)-62)//T_(1)`
Solving `T_(2) = 310 K = 37^(@)C, T_(1) = 372 K = 99^(@)C`