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A diatomic gas initially at 18^(@)C is c...

A diatomic gas initially at `18^(@)C` is compressed adiabatically to one-eight of its original volume. The temperature after compression will be

A

`18^(@)C `

B

`887^(@)C `

C

`395^(@)C `

D

`144^(@)C `

Text Solution

Verified by Experts

The correct Answer is:
C
`T_(2) = T_(1) (V_(1)//V_(2))^(gamma-1) = 291 xx (8)^(1.4-1) = 66.8.5 K = 395^(@)C`.
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