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In an adiabatic change the pressure and ...

In an adiabatic change the pressure and temperature of monoatomic gas are related as `P prop T^(c )` where C equal

A

`2//5`

B

`5//2`

C

`3//5`

D

`5//3 `

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The correct Answer is:
To solve the problem, we need to establish the relationship between pressure (P) and temperature (T) for a monoatomic gas undergoing an adiabatic process. The steps are as follows: ### Step 1: Understand the Adiabatic Process In an adiabatic process, there is no heat exchange with the surroundings. For an ideal gas, the relationship between pressure (P), volume (V), and temperature (T) can be described using the equation: \[ PV^{\gamma} = \text{constant} \] where \(\gamma\) (gamma) is the heat capacity ratio \(C_p/C_v\). ### Step 2: Express Volume in Terms of Pressure and Temperature Using the ideal gas law: \[ PV = nRT \] we can express volume (V) as: \[ V = \frac{nRT}{P} \] ### Step 3: Substitute Volume into the Adiabatic Equation Substituting the expression for V into the adiabatic equation: \[ P \left(\frac{nRT}{P}\right)^{\gamma} = \text{constant} \] This simplifies to: \[ P^{1 - \gamma} (nRT)^{\gamma} = \text{constant} \] ### Step 4: Rearranging the Equation Rearranging gives us: \[ P^{1 - \gamma} \propto (nRT)^{\gamma} \] This implies: \[ P^{1 - \gamma} \propto T^{\gamma} \] ### Step 5: Expressing Pressure in Terms of Temperature From the proportional relationship, we can express pressure as: \[ P \propto T^{\frac{\gamma}{1 - \gamma}} \] ### Step 6: Identifying the Value of C Comparing this with the given relationship \(P \propto T^C\), we find that: \[ C = \frac{\gamma}{1 - \gamma} \] ### Step 7: Finding the Value of Gamma for Monoatomic Gas For a monoatomic gas, the value of \(\gamma\) is: \[ \gamma = \frac{C_p}{C_v} = \frac{5}{3} \] ### Step 8: Substituting Gamma into the Expression for C Substituting \(\gamma\) into the expression for C: \[ C = \frac{\frac{5}{3}}{1 - \frac{5}{3}} = \frac{\frac{5}{3}}{-\frac{2}{3}} = -\frac{5}{2} \] ### Step 9: Finalizing the Value of C Thus, we find: \[ C = \frac{5}{2} \] ### Conclusion The value of C for the relationship between pressure and temperature in an adiabatic process for a monoatomic gas is: \[ C = \frac{5}{2} \]

To solve the problem, we need to establish the relationship between pressure (P) and temperature (T) for a monoatomic gas undergoing an adiabatic process. The steps are as follows: ### Step 1: Understand the Adiabatic Process In an adiabatic process, there is no heat exchange with the surroundings. For an ideal gas, the relationship between pressure (P), volume (V), and temperature (T) can be described using the equation: \[ PV^{\gamma} = \text{constant} \] where \(\gamma\) (gamma) is the heat capacity ratio \(C_p/C_v\). ### Step 2: Express Volume in Terms of Pressure and Temperature ...
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