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A wall is made of equally thick layers A and B of different matierals. Thermal conduvtivity of A is twice that of B. In the stedy state, the temperature difference across the wall is `36^(@)C` . The temperature difference across the layer A is

A

`6^(@)C`

B

`12^(@)C `

C

`18^(@)C `

D

`24^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B
`K_(1)A_(1) DeltaT/d_(1) = K_(2)A_(2) (36-DeltaT)//d_(2)`
`2 DeltaT - 36-Deltat, Deltat = 12^(@)C`
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