A linear harmonic oscillator of force constant `2 xx 10^(6) Nm^(-1)` and amplitude 0.01 m has a total mechanical energy of 160 J. Its

Options

A. maximum potential energy is 100 J
B. maximum kinetic energy is 100 J
C. maximum potential energy is 160 J
D. maximum potential energy is zero

Answer

B, C

Explanation

`(1//2)ka^(2) = (1//2) xx 2 xx 10^(6) xx (0.01)^(2) = 100 J`
Max K.E. ` = 100 J. "Max" P.E. = 160 J`