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A transverse wave is represented by the ...

A transverse wave is represented by the equation
`y = y_(0) sin (2pi)/(lambda) (vt-x)`
For what value of `lambda` is the particle velocity equal to two time the wave velocity ?

A

`lambda = 2pi y_(0)`

B

`lambda = 2pi y_(0)//3`

C

`lambda = piy_(0)//2`

D

`lambda = piy_(0)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \(\lambda\) for which the particle velocity is equal to two times the wave velocity. ### Step-by-Step Solution: 1. **Understand the Wave Equation**: The transverse wave is represented by the equation: \[ y = y_0 \sin\left(\frac{2\pi}{\lambda}(vt - x)\right) \] Here, \(y_0\) is the amplitude, \(\lambda\) is the wavelength, \(v\) is the wave velocity, and \(x\) and \(t\) are the position and time variables, respectively. 2. **Find the Particle Velocity**: The particle velocity \(v_p\) can be found by differentiating the displacement \(y\) with respect to time \(t\): \[ v_p = \frac{dy}{dt} \] Using the chain rule, we differentiate: \[ v_p = y_0 \cdot \cos\left(\frac{2\pi}{\lambda}(vt - x)\right) \cdot \frac{d}{dt}\left(\frac{2\pi}{\lambda}(vt - x)\right) \] The derivative of \((vt - x)\) with respect to \(t\) is \(v\), so: \[ v_p = y_0 \cdot \cos\left(\frac{2\pi}{\lambda}(vt - x)\right) \cdot \frac{2\pi v}{\lambda} \] 3. **Maximum Particle Velocity**: The maximum value of the cosine function is 1, so the maximum particle velocity \(v_{p_{max}}\) is: \[ v_{p_{max}} = y_0 \cdot \frac{2\pi v}{\lambda} \] 4. **Set Particle Velocity Equal to Two Times Wave Velocity**: We are given that the particle velocity is equal to two times the wave velocity: \[ v_{p_{max}} = 2v \] Substituting the expression for \(v_{p_{max}}\): \[ y_0 \cdot \frac{2\pi v}{\lambda} = 2v \] 5. **Simplify the Equation**: We can cancel \(v\) from both sides (assuming \(v \neq 0\)): \[ y_0 \cdot \frac{2\pi}{\lambda} = 2 \] Rearranging gives: \[ \frac{2\pi y_0}{\lambda} = 2 \] 6. **Solve for \(\lambda\)**: Multiplying both sides by \(\lambda\) and dividing by 2 gives: \[ \lambda = \pi y_0 \] ### Final Answer: The value of \(\lambda\) for which the particle velocity is equal to two times the wave velocity is: \[ \lambda = \pi y_0 \]

To solve the problem, we need to find the value of \(\lambda\) for which the particle velocity is equal to two times the wave velocity. ### Step-by-Step Solution: 1. **Understand the Wave Equation**: The transverse wave is represented by the equation: \[ y = y_0 \sin\left(\frac{2\pi}{\lambda}(vt - x)\right) ...
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