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The intensity of sound wave while passin...

The intensity of sound wave while passing through an elastic medium falls down by 10% as it covers one metre distance through the medium. If the initial intensity of the sound wave was 100 decibels, its value after it has passes through 3 metre thickness of the medium will be

A

70 decibel

B

72.9 decibel

C

81 decibel

D

60 decibel

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The correct Answer is:
To solve the problem step by step, we will analyze the decrease in intensity of the sound wave as it passes through the elastic medium. ### Step 1: Understand the initial intensity The initial intensity of the sound wave is given as 100 decibels. ### Step 2: Determine the intensity reduction per meter The intensity of the sound wave falls by 10% for every 1 meter it travels through the medium. This means that after 1 meter, the intensity will be: \[ I' = I \times (1 - 0.10) = I \times 0.90 \] Where \( I \) is the initial intensity. ### Step 3: Calculate the intensity after 1 meter Using the initial intensity: \[ I' = 100 \times 0.90 = 90 \text{ decibels} \] ### Step 4: Calculate the intensity after 2 meters The intensity after the second meter will again fall by 10% of the intensity after the first meter: \[ I'' = I' \times 0.90 = 90 \times 0.90 = 81 \text{ decibels} \] ### Step 5: Calculate the intensity after 3 meters The intensity after the third meter will again fall by 10% of the intensity after the second meter: \[ I''' = I'' \times 0.90 = 81 \times 0.90 = 72.9 \text{ decibels} \] ### Final Result Thus, the intensity of the sound wave after it has passed through 3 meters of the medium is: \[ I''' = 72.9 \text{ decibels} \] ### Conclusion The answer is 72.9 decibels. ---

To solve the problem step by step, we will analyze the decrease in intensity of the sound wave as it passes through the elastic medium. ### Step 1: Understand the initial intensity The initial intensity of the sound wave is given as 100 decibels. ### Step 2: Determine the intensity reduction per meter The intensity of the sound wave falls by 10% for every 1 meter it travels through the medium. This means that after 1 meter, the intensity will be: \[ I' = I \times (1 - 0.10) = I \times 0.90 \] ...
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