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A tube closed at one end and containing air produced, when excited the fundamental note of frequency `512 H_(Z)`. If the tube is opened at both ends, the fundamental frequency that can be exited is (in `H_(Z)`)
(a) `1024` (b) `512` (c ) `256` (d) `128`

A

1024

B

512

C

256

D

128

Text Solution

Verified by Experts

The correct Answer is:
A

`512 = v//4l, n = v//2l, 512//n = 1//2, n = 1024` Hz
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