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Two identical straight wires are stretch...

Two identical straight wires are stretched so as to products `6 beats// s` when vibrating simultaneously. On changing the tension slightly in one of them, the beat frequency remains unchanged. Denoting by , `T_(1)` the higher and `T_(2)` the lower, initial tensions in the strings, then it could be said that that while making the above changes in tension

A

`T_(2)` was decreased

B

`T_(2)` was increased

C

`T_(1)` was increased

D

`T_(1)` was decreased

Text Solution

Verified by Experts

The correct Answer is:
B, D
`n prop sqrt(T_(1))` But `T_(1) gt T_(2)`, So `n_(1) gt n_(2)`, and `n_(1)-n_(2) = 6` We can makes `n_(2) - n_(1) = 6`, by increasing `T_(2) or decreasing `T_(1)`
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