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A simple pendulum is suspended from the ...

A simple pendulum is suspended from the ceiling of a stationary elevator and it oscillates with a small amplitude if the elevator accelerates upwards, the

A

frequency of oscillation of pendulum increases

B

frequency of the oscillations of the pendulum decreases

C

pendulum stops oscillating

D

time period of oscillations remain same but the amplitude increases

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The correct Answer is:
To solve the problem regarding the behavior of a simple pendulum in an upward accelerating elevator, we can follow these steps: ### Step 1: Understand the System A simple pendulum consists of a mass (bob) attached to a string of length \( L \) that swings back and forth. The motion of the pendulum is influenced by gravitational force. ### Step 2: Identify the Effective Gravity When the elevator accelerates upward with acceleration \( a \), the effective gravitational force acting on the pendulum changes. The effective acceleration due to gravity \( g_{\text{effective}} \) can be expressed as: \[ g_{\text{effective}} = g + a \] where \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)). ### Step 3: Write the Formula for Time Period The time period \( T \) of a simple pendulum is given by: \[ T = 2\pi \sqrt{\frac{L}{g}} \] When the elevator accelerates upward, we replace \( g \) with \( g_{\text{effective}} \): \[ T' = 2\pi \sqrt{\frac{L}{g + a}} \] ### Step 4: Analyze the Effect on Time Period Since \( g + a > g \), it follows that: \[ T' = 2\pi \sqrt{\frac{L}{g + a}} < T = 2\pi \sqrt{\frac{L}{g}} \] This means that the time period \( T' \) decreases when the elevator accelerates upward. ### Step 5: Determine the Effect on Frequency Frequency \( f \) is the reciprocal of the time period: \[ f = \frac{1}{T} \] Since the time period \( T' \) decreases, the frequency \( f' \) will increase: \[ f' = \frac{1}{T'} > f = \frac{1}{T} \] ### Conclusion Thus, when the elevator accelerates upwards, the frequency of oscillation of the pendulum increases. ### Final Answer The correct option is **A: frequency of oscillation of pendulum increases**. ---
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