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Acceleration due to gravity at any point...

Acceleration due to gravity at any point inside the earth

A

varies inversely as the square of the distance from the centre

B

is independent of the distance from the centre

C

is directly proportional to the distance from the centre

D

is inversely proportional to the distance from centre

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The correct Answer is:
To find the acceleration due to gravity at any point inside the Earth, we can follow these steps: ### Step 1: Understand the formula for acceleration due to gravity The acceleration due to gravity (g) at a distance r from the center of the Earth is given by the formula: \[ g = \frac{G M}{r^2} \] where: - \( G \) is the universal gravitational constant, - \( M \) is the mass of the Earth, - \( r \) is the distance from the center of the Earth. ### Step 2: Consider the scenario inside the Earth When we are inside the Earth, the effective mass that contributes to the gravitational force is only the mass that is at a distance less than r from the center. According to the shell theorem, the gravitational force inside a uniform spherical shell of mass is zero. Therefore, only the mass of the sphere of radius r contributes to the gravitational force. ### Step 3: Modify the formula for inside the Earth For a point inside the Earth at a distance r from the center, the formula for acceleration due to gravity becomes: \[ g' = \frac{G M'}{r^2} \] where \( M' \) is the mass of the sphere of radius r. ### Step 4: Relate mass M' to the volume and density Assuming the Earth has a uniform density \( \rho \), the mass \( M' \) can be expressed as: \[ M' = \rho \cdot V = \rho \cdot \frac{4}{3} \pi r^3 \] Substituting this back into the equation for g': \[ g' = \frac{G \cdot \rho \cdot \frac{4}{3} \pi r^3}{r^2} \] This simplifies to: \[ g' = \frac{4}{3} \pi G \rho r \] ### Step 5: Conclusion From the derived formula, we can see that the acceleration due to gravity inside the Earth is directly proportional to the distance r from the center. Thus, as you move towards the center of the Earth, the acceleration due to gravity decreases linearly with r. ### Final Answer The acceleration due to gravity at any point inside the Earth is given by: \[ g' = \frac{4}{3} \pi G \rho r \] This indicates that \( g' \) varies linearly with the distance from the center of the Earth. ---
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