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The weight of a body will increase signi...

The weight of a body will increase significantly it is taken

A

from the pole of the equator

B

from the equator to the pole

C

to the top of a momentum

D

to the centre of the earth

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The correct Answer is:
To solve the question regarding the change in weight of a body as it is moved from the equator to the pole, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Weight and Gravity**: - Weight (W) of a body is given by the formula: \[ W = mg \] where \( m \) is the mass of the body and \( g \) is the acceleration due to gravity. 2. **Acceleration due to Gravity**: - The value of \( g \) varies with latitude due to the Earth's rotation and its shape. The formula for \( g \) at a latitude \( \theta \) is: \[ g' = g - R_e \omega^2 \cos^2(\theta) \] where: - \( g' \) is the effective gravity at latitude \( \theta \), - \( R_e \) is the radius of the Earth, - \( \omega \) is the angular velocity of the Earth. 3. **Evaluating at the Equator**: - At the equator, \( \theta = 0^\circ \): \[ g' = g - R_e \omega^2 \cos(0) = g - R_e \omega^2 \] Hence, \( g' \) is minimum at the equator. 4. **Evaluating at the Pole**: - At the pole, \( \theta = 90^\circ \): \[ g' = g - R_e \omega^2 \cos(90) = g - 0 = g \] Thus, \( g' \) is maximum at the pole. 5. **Comparing Weights**: - As we move from the equator to the pole, \( g' \) increases from its minimum value at the equator to its maximum value at the pole. - Since weight is directly proportional to \( g \), the weight of the body will also increase as it moves from the equator to the pole. 6. **Conclusion**: - Therefore, the weight of a body will increase significantly when taken from the equator to the pole. ### Final Answer: The weight of a body will increase significantly if it is taken from the equator to the pole.
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