An open organ pipe emitts sound of frequency 480Hz. When temperature was `47^@C`. Calculate the frequency of sound emitted if the temperature falls to `27^@C,` assuming that there is no change in the length of the pipe.

Explanation

Let the velocity and frequency at `47^@C" be "v_(1) and v_(1) and at 27^@C" be "V_(2) and v_(2)` respectively
For open pipe `v=V/(2L)`
`v_(1)=(V_(1))/(2L) and v_(2)=(V_(2))/(2L)`
`v_(1)/v_(2)=V_(2)/V_(2) =sqrt((273+47)/(273+27))=sqrt((320)/(300))`
`v_(1)=480Hz, v_(2)=?`
`v_(2)=480 sqrt((300)/(320))`
=464.75Hz