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A set of 24 tuming forka is arranged in ...

A set of 24 tuming forka is arranged in series of Locrening frequencies. If each tuning fork gives 4 beats/sec with the preceding one and the last fork is found to be the octave of the first, calculate the frequences of the first and the last.

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To solve the problem, we need to find the frequencies of the first and the last tuning fork in a series of 24 tuning forks arranged in increasing frequencies, where each fork produces 4 beats per second with the preceding one, and the last fork is an octave of the first. ### Step-by-Step Solution: 1. **Define the Variables:** Let the frequency of the first tuning fork be \( f \). Since the last fork is an octave of the first, its frequency will be \( 2f \). 2. **Understanding Beats:** ...
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