Tivo sitar strings A and B playing the note 'Ga'are slightly out of tunc and produce bedis of frequency 6 Hz. The tension in the string A is slightly reduced and the bear frequency is found to reduce to 3 Hz If the original frequency of A is 324 Hz, what is the frequency of B?

Explanation

To solve the problem step by step, we will use the information given about the frequencies and the concept of beat frequency.

### Step 1: Understand the concept of beat frequency
The beat frequency is the difference between the frequencies of two strings that are slightly out of tune. This is given by the formula:
\[ n = |f_A - f_B| \]
where \( n \) is the beat frequency, \( f_A \) is the frequency of string A, and \( f_B \) is the frequency of string B.

### Step 2: Assign the known values
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