If one sound wave has twice the pressure amplitude of the another sound in the same medium, find the ratio of the intensities of the two sounds ?

Two sound waves one in air and the other in fresh water are equal in intensity. (a) Find the ratio of pressure amplitude of the wave in water to that of the wave in air. (b) If the pressure amplitudes of the waves are equal then what will be the ratio of the intensities of the waves. [ V_(sound) = 340 m//s in air & density of air = 1.25 kg//m^(3), V_(sound) = 1530 m//s in water, density of water = 1000 kg//m^(3) ]

The intensities of two sound waves, one in air and the second one in water are equal (i) What is the ratio of the pressure amplitude of the wave in water to that of the wave in air? If the pressure amplitudes are equal instead, what is the ratio of the intensities of hte waves? Density of air is 1.293 kg//m^2 . Velocity of sound in air and water are 330ms^(-1) and 1450ms^(-1) respectively.

Larger is the amplitude, feeble is the sound

By reducing the amplitude of a sound wave, its :

Ratio of amplitude for two wave is 1:6.Find the ratio of intensity?

Ratio of amplitude for two wave is 1:2 .Find the ratio of intensity?

Ratio of amplitude for two wave is 1:4 .Find the ratio of intensity?

Ratio of amplitude for two wave is 11:4.Find the ratio of intensity?

Ratio of amplitude for two wave is 11:6.Find the ratio of intensity?

Ratio of amplitude for two wave is 15:9.Find the ratio of intensity?