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Write down the expression for the nth ha...

Write down the expression for the nth harmonic in (i) closed pipe (ii) an open pipe.

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What should be the ratio of the lengths of a closed pipe and an open pipe, so that the frequency of their First overtones are the same.

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An open pipe is suddenly closed at one end with the result that the frequency of third harmonic of the closed pipe is found to be higher by 100 Hz then the fundamental frequency of the open pipe. The fundamental frequency of the open pipe is

[Q. Nos. 3-4] Difference in frequencies between 3rd overtone of closed pipe and 5th haronic of the same pipe is 400 Hz. Futher 3rd hormonic of this closed pipe os equal to 6th hormonic of another open pipe. Fundamental frequencies of closed pipe and open pipe are: a) 200 Hz, 400 Hz b) 150 Hz, 75 Hz c) 200 Hz, 100Hzz d) 400 Hz, 300Hz

[Q. Nos. 3-4] Difference in frequencies between 3rd overtone of closed pipe and 5th harmonic of the same pipe is 400 Hz. Further 3rd hormonic of this closed pipe is equal to 6th hormonic of another open pipe. If speed sound is 330 m/s. Then lengths of closed pipe and open pipe are a) 0.4125 m, 0.825 m b) 3.3m, 1.65 m c) 0.825 m, 0.825 m d) 1.65 m, 0.825 m

First overtone frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. Further nth harmonic of closed organ pipe is also equal to the mth harmonic of open pipe, where n and m are (A)5,4 (B)7,5 (C)9,6 (D)7,3

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