An organ pipe has a frequency n. If its length is doubled what happens to the frequency?

A closed tube has a frequency n. If its length is doubled and radius is halved its frequency will become

A string vibrates with a frequency 200Hz. Its length is doubled and its tension is altered until it begin to vibrate with frequency 300Hz. What is the ratio of the new tension to the original tension?

The fundamental frequency of an open organ pipe is n. If one of its ends is closed then its fundamental frequency will be –

The first overtone of an open pipe has frequency n. The first ovetone of a closed pipe of the same length will have frequency

The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe L metre long. The length of the open pipe will be

The first overtone of an open organ pipe beats with the first overtone of a closed organ pipe with a beat frequency 2.2 Hz . The fundamental frequency of the closed organ pipe is 110 Hz , find the lengths of the pipes . Take velocity of sound = 330 m//s .

An open organ pipe has a fundamental frequency of 300 H_(Z) . The first overtone of a closed organ pipe has the same frequency as the first overtone of this open pipe . How long is each pipe ? (Speed of sound in air = 330 m//s )

The fundamental frequency of an open organi pipe is 330 Hz. The first overtone of a closed organ pipe has the same frequency as the first overtone of the open pipe. How long is each pipe 2 Velocity of sound =330 m/s.

The fundamental note produced by a closed organ pipe is of frequency v. The fundamental note produced by an open organ pipe of same length will be of frequency

An open pipe is 85 cm long. If the velocity of sound is 340 ms^(-1) , find the frequency of the fundamental note of the pipe. What would be the length of a closed pipe which produces a fundamental note of the same frequency?