A broadcasting station radiates at a frequency of 555 kHz. What is the wavelength ? Given velocity of wave is `3 xx 10^8 ms^(-1)`.

Answer

To find the wavelength of the wave radiated by the broadcasting station, we can use the wave equation:

\[ \lambda = \frac{v}{f} \]

where:
- \(\lambda\) is the wavelength,
- \(v\) is the velocity of the wave, and
- \(f\) is the frequency of the wave.

### Step 1: Identify the given values
- Frequency \(f = 555 \text{ kHz} = 555 \times 10^3 \text{ Hz}\)
- Velocity \(v = 3 \times 10^8 \text{ m/s}\)

### Step 2: Substitute the values into the wave equation
Now, we can substitute the values into the equation:

\[ \lambda = \frac{3 \times 10^8 \text{ m/s}}{555 \times 10^3 \text{ Hz}} \]

### Step 3: Perform the calculation
Calculating the denominator:

\[ 555 \times 10^3 = 555000 \text{ Hz} \]

Now, we can perform the division:

\[ \lambda = \frac{3 \times 10^8}{555000} \]

Calculating this gives:

\[ \lambda \approx 541.44 \text{ m} \]

### Step 4: Round the answer
Rounding this to three significant figures, we get:

\[ \lambda \approx 5.41 \times 10^2 \text{ m} \]

### Final Answer
The wavelength is approximately \(5.41 \times 10^2 \text{ meters}\).

---