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A plane progressive wave is given by y=0...

A plane progressive wave is given by `y=0.3 sin ((220)/(7) t -25.12x)`
Find the wavelength and the phase difference between two points at r= 0.3 m and r=0.425 m. Also find the maximum particle velocity.

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To solve the problem step by step, we will analyze the given wave equation and extract the necessary information. ### Given Wave Equation: \[ y = 0.3 \sin\left(\frac{220}{7} t - 25.12 x\right) \] ### Step 1: Find the Wavelength The general form of a plane progressive wave is: \[ y = A \sin(\omega t - kx) \] where: - \( A \) is the amplitude, - \( \omega \) is the angular frequency, - \( k \) is the wave number. From the given equation, we can identify: - \( k = 25.12 \) The wavelength \( \lambda \) is related to the wave number \( k \) by the formula: \[ \lambda = \frac{2\pi}{k} \] Substituting the value of \( k \): \[ \lambda = \frac{2\pi}{25.12} \] Calculating: \[ \lambda \approx \frac{6.2832}{25.12} \approx 0.25 \, \text{m} \] ### Step 2: Find the Phase Difference To find the phase difference between two points at \( r_1 = 0.3 \, \text{m} \) and \( r_2 = 0.425 \, \text{m} \), we use the formula: \[ \Delta \phi = -k \Delta r \] where: \[ \Delta r = r_2 - r_1 = 0.425 - 0.3 = 0.125 \, \text{m} \] Substituting the values: \[ \Delta \phi = -25.12 \times 0.125 \] Calculating: \[ \Delta \phi = -3.14 \] ### Step 3: Find the Maximum Particle Velocity The maximum particle velocity \( V_{\text{max}} \) can be found by differentiating the wave equation with respect to time \( t \): \[ V = \frac{dy}{dt} = \omega A \cos(\omega t - kx) \] From the wave equation, we have: - \( \omega = \frac{220}{7} \) - \( A = 0.3 \) Thus, \[ V_{\text{max}} = \omega A = \left(\frac{220}{7}\right) \times 0.3 \] Calculating: \[ V_{\text{max}} \approx \frac{220 \times 0.3}{7} \approx \frac{66}{7} \approx 9.428 \, \text{m/s} \] ### Final Answers: - Wavelength \( \lambda \approx 0.25 \, \text{m} \) - Phase difference \( \Delta \phi \approx -3.14 \) - Maximum particle velocity \( V_{\text{max}} \approx 9.428 \, \text{m/s} \) ---
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