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A copper rod 1 m long and clamped at a p...

A copper rod 1 m long and clamped at a point distant 25 cm, from its end is set in longitudinal vibrations and is used to produce stationary waves is a Kundt's tube containing air at `30^@C.` Heaps of lycopodium dust are found to be 4.95 cm apart. What is the velocity of longitudinal waves in copper ? Velocity of sound in air at `0^@C"= 332 m/s."`

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To find the velocity of longitudinal waves in copper, we can use the relationship between the velocities of sound in different media and the physical parameters of the system. Here’s a step-by-step solution: ### Step 1: Identify Given Values - Length of the copper rod (L) = 25 cm = 0.25 m - Distance between heaps of lycopodium dust (ΔL) = 4.95 cm = 0.0495 m - Velocity of sound in air at 0°C (V_air) = 332 m/s ### Step 2: Use the Relationship Between Velocities The relationship between the velocities of sound in copper (V_copper) and air is given by the formula: \[ \frac{V_{copper}}{V_{air}} = \frac{2L}{\Delta L} \] ### Step 3: Rearrange the Formula to Solve for V_copper We can rearrange the formula to find the velocity of sound in copper: \[ V_{copper} = V_{air} \times \frac{2L}{\Delta L} \] ### Step 4: Substitute the Known Values Now, substitute the known values into the equation: \[ V_{copper} = 332 \, \text{m/s} \times \frac{2 \times 0.25 \, \text{m}}{0.0495 \, \text{m}} \] ### Step 5: Calculate the Value First, calculate the fraction: \[ \frac{2 \times 0.25}{0.0495} = \frac{0.5}{0.0495} \approx 10.101 \] Now, multiply by the velocity of sound in air: \[ V_{copper} \approx 332 \, \text{m/s} \times 10.101 \approx 3353.53 \, \text{m/s} \] ### Final Answer The velocity of longitudinal waves in copper is approximately **3353.53 m/s**. ---
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