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Wavelength of two notes in air are 68/17...

Wavelength of two notes in air are 68/176 m and 68/174 m each note produces five beats per second with a third note of fixed frequency. Calculate the velocity of sound in air?

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To solve the problem, we need to calculate the velocity of sound in air using the given wavelengths of two notes and the information about the beats produced. ### Step-by-Step Solution: 1. **Identify the Wavelengths**: - Wavelength of note 1, \( \lambda_1 = \frac{68}{176} \, \text{m} \) - Wavelength of note 2, \( \lambda_2 = \frac{68}{174} \, \text{m} \) 2. **Determine the Beat Frequency**: - The beat frequency is given as 5 beats per second. Since there are two notes producing beats with a third note of fixed frequency, the total beat frequency is \( f_1 - f_2 = 10 \, \text{Hz} \). 3. **Use the Frequency Formula**: - The frequency \( f \) is related to the velocity \( v \) and wavelength \( \lambda \) by the formula: \[ f = \frac{v}{\lambda} \] - For note 1: \[ f_1 = \frac{v}{\lambda_1} = \frac{v}{\frac{68}{176}} = \frac{176v}{68} \] - For note 2: \[ f_2 = \frac{v}{\lambda_2} = \frac{v}{\frac{68}{174}} = \frac{174v}{68} \] 4. **Set Up the Equation for Beat Frequency**: - From the beat frequency: \[ f_1 - f_2 = 10 \, \text{Hz} \] - Substitute \( f_1 \) and \( f_2 \): \[ \frac{176v}{68} - \frac{174v}{68} = 10 \] - Simplifying this gives: \[ \frac{(176 - 174)v}{68} = 10 \] \[ \frac{2v}{68} = 10 \] 5. **Solve for Velocity \( v \)**: - Cross-multiply to solve for \( v \): \[ 2v = 10 \times 68 \] \[ 2v = 680 \] \[ v = \frac{680}{2} = 340 \, \text{m/s} \] 6. **Conclusion**: - The velocity of sound in air is \( v = 340 \, \text{m/s} \).
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