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A car B, with a hom of frequency 700 Hz ...

A car B, with a hom of frequency 700 Hz moves with a velocity `90 kmh^(-1).` It approaches another car A, coming towards it with a velocity `72 kmh^(-1).` Calculate the apparent frequency of the sound heard by the driver in the car A (a) before crossing (b) after crossing ? Velocity of sound `=350 ms^(-1)`.

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To solve the problem of calculating the apparent frequency of the sound heard by the driver in car A before and after crossing car B, we will use the Doppler effect formula. ### Given Data: - Frequency of the horn (f) = 700 Hz - Velocity of car B (source, Vs) = 90 km/h - Velocity of car A (observer, V0) = 72 km/h - Velocity of sound (V) = 350 m/s ### Step 1: Convert velocities from km/h to m/s To convert km/h to m/s, we use the conversion factor \( \frac{5}{18} \). - For car B (Vs): \[ Vs = 90 \times \frac{5}{18} = 25 \text{ m/s} \] - For car A (V0): \[ V0 = 72 \times \frac{5}{18} = 20 \text{ m/s} \] ### Step 2: Calculate apparent frequency before crossing When both cars are approaching each other, the formula for apparent frequency (f') is given by: \[ f' = f \frac{V + V0}{V - Vs} \] Where: - f = frequency of the source - V = speed of sound - V0 = speed of the observer (car A) - Vs = speed of the source (car B) Substituting the values: \[ f' = 700 \frac{350 + 20}{350 - 25} \] Calculating the numerator and denominator: \[ f' = 700 \frac{370}{325} \] Calculating further: \[ f' = 700 \times 1.13846 \approx 796.92 \text{ Hz} \] ### Step 3: Calculate apparent frequency after crossing After crossing, the formula for apparent frequency (f') changes as the observer and source are moving away from each other: \[ f' = f \frac{V - V0}{V + Vs} \] Substituting the values: \[ f' = 700 \frac{350 - 20}{350 + 25} \] Calculating the numerator and denominator: \[ f' = 700 \frac{330}{375} \] Calculating further: \[ f' = 700 \times 0.88 \approx 616 \text{ Hz} \] ### Final Answers: (a) The apparent frequency before crossing is approximately **796.92 Hz**. (b) The apparent frequency after crossing is approximately **616 Hz**. ---
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