Both sodium sulphate `(Na_(2)SO_(4))` and sodium sulphite `(Na_(2)SO_(3))` are the compounds of sodium, sulphur and oxygen. By calculations prove that the quantity of oxygen in sodium sulphate is greater than that in sodium sulphite. (R.A.M. : Na = 23, S = 32, O = 16.]

Explanation

To prove that the quantity of oxygen in sodium sulfate `(Na₂SO₄)` is greater than that in sodium sulfite `(Na₂SO₃)`, we will calculate the molecular weight of both compounds and then find the percentage of oxygen in each.

### Step 1: Calculate the molecular weight of Sodium Sulfate `(Na₂SO₄)`

1. **Identify the atomic masses**:
- Sodium (Na) = 23 g/mol
- Sulfur (S) = 32 g/mol
- Oxygen (O) = 16 g/mol
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