A compound is composed of 43.4% Na, 11.32% C and rest of oxygen by mass. Derive a empirical formula of the compound. (R.A.M.: C = 12, O = 16, Na - 23)

Explanation

To derive the empirical formula of the compound composed of 43.4% sodium (Na), 11.32% carbon (C), and the rest as oxygen (O), we will follow these steps:

### Step 1: Determine the percentage of oxygen
To find the percentage of oxygen, we subtract the percentages of sodium and carbon from 100%.

\[ \text{Percentage of O} = 100\% - (43.4\% + 11.32\%) = 100\% - 54.72\% = 45.28\% \]
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