Calcium hydroxide and ammonium chloride react to give ammonia as per equation:
`Ca(OH)_(2) + 2 NH_(4)Cl to CaCl_(2) + 2 NH_(3) + 2 H_(2) O `
In a reaction, `5.35 `g of ammonium chloride were consumed . Calculate
The mass of calcium chloride formed.

Explanation

To solve the problem of calculating the mass of calcium chloride formed when 5.35 g of ammonium chloride reacts, we will follow these steps:

### Step 1: Write the balanced chemical equation
The balanced chemical equation for the reaction is:
\[ \text{Ca(OH)}_2 + 2 \text{NH}_4\text{Cl} \rightarrow \text{CaCl}_2 + 2 \text{NH}_3 + 2 \text{H}_2\text{O} \]

### Step 2: Calculate the molar mass of ammonium chloride (NH₄Cl)
The molar mass of NH₄Cl can be calculated as follows:
- N: 14 g/mol
- H: 1 g/mol (4 H atoms = 4 g/mol)
- Cl: 35.5 g/mol

Thus, the molar mass of NH₄Cl:
\[ \text{Molar mass of NH}_4\text{Cl} = 14 + 4 + 35.5 = 53.5 \text{ g/mol} \]

### Step 3: Calculate the moles of ammonium chloride (NH₄Cl)
Using the formula:
\[ \text{Moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]

Substituting the values:
\[ \text{Moles of NH}_4\text{Cl} = \frac{5.35 \text{ g}}{53.5 \text{ g/mol}} = 0.1 \text{ moles} \]

### Step 4: Determine the moles of calcium chloride (CaCl₂) produced
From the balanced equation, we see that 2 moles of NH₄Cl produce 1 mole of CaCl₂. Therefore, the relationship can be expressed as:
\[ 2 \text{ moles of NH}_4\text{Cl} \rightarrow 1 \text{ mole of CaCl}_2 \]

Thus, for 0.1 moles of NH₄Cl:
\[ \text{Moles of CaCl}_2 = \frac{0.1}{2} = 0.05 \text{ moles} \]

### Step 5: Calculate the molar mass of calcium chloride (CaCl₂)
The molar mass of CaCl₂ can be calculated as follows:
- Ca: 40 g/mol
- Cl: 35.5 g/mol (2 Cl atoms = 71 g/mol)

Thus, the molar mass of CaCl₂:
\[ \text{Molar mass of CaCl}_2 = 40 + 71 = 111 \text{ g/mol} \]

### Step 6: Calculate the mass of calcium chloride formed
Using the formula:
\[ \text{Mass} = \text{Moles} \times \text{Molar mass} \]

Substituting the values:
\[ \text{Mass of CaCl}_2 = 0.05 \text{ moles} \times 111 \text{ g/mol} = 5.55 \text{ g} \]

### Final Answer
The mass of calcium chloride formed is **5.55 g**.

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