Carbon monoxide combines with oxygen to form carbon dioxide according to the equation:
`2CO(g) + O_(2)(g) to 2CO_(2)(g)` .
`200 cm^(3)` of carbon monoxide is mixed with `200 cm^(3)` of oxygen at room temperature and ignited.
Calculate the volume of carbon dioxide formed when cooled to room temperature.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Write the balanced chemical equation
The balanced chemical equation for the reaction between carbon monoxide (CO) and oxygen (O2) to form carbon dioxide (CO2) is:
\[ 2 \text{CO} (g) + \text{O}_2 (g) \rightarrow 2 \text{CO}_2 (g) \]

### Step 2: Identify the volumes of reactants
We are given:
- Volume of carbon monoxide (CO) = 200 cm³
- Volume of oxygen (O2) = 200 cm³

### Step 3: Determine the stoichiometry of the reaction
From the balanced equation, we see that:
- 2 volumes of CO react with 1 volume of O2 to produce 2 volumes of CO2.

This means:
- 2 volumes of CO produce 2 volumes of CO2, which implies that 1 volume of CO produces 1 volume of CO2.

### Step 4: Calculate the limiting reactant
According to the stoichiometry:
- 2 volumes of CO require 1 volume of O2.
- Therefore, 200 cm³ of CO would require \( \frac{200}{2} = 100 \) cm³ of O2.

Since we have 200 cm³ of O2 available, CO is the limiting reactant.

### Step 5: Calculate the volume of CO2 produced
Since 200 cm³ of CO will produce an equal volume of CO2:
- Volume of CO2 produced = Volume of CO = 200 cm³.

### Step 6: Final volume of CO2 at room temperature
When cooled to room temperature, the volume of CO2 remains the same, as gases behave ideally under these conditions.

Thus, the volume of carbon dioxide formed when cooled to room temperature is:
- **200 cm³**

### Summary of the solution:
- The balanced equation is \( 2 \text{CO} + \text{O}_2 \rightarrow 2 \text{CO}_2 \).
- 200 cm³ of CO reacts with 100 cm³ of O2.
- The volume of CO2 produced is 200 cm³.