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When 1 mol of zinc was treated with suff...

When 1 mol of zinc was treated with sufficient quantity of hydrochloric acid, the whole of Zn was consumed. In the reaction, hydrogen gas was liberated and zinc chloride was formed. State
The moles of HCl required to react with 1 mole of zinc.

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To determine the moles of hydrochloric acid (HCl) required to react with 1 mole of zinc (Zn), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction between zinc and hydrochloric acid can be written as: \[ \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] 2. **Balance the Reaction**: To balance the reaction, we need to ensure that the number of atoms for each element is the same on both sides. The balanced equation is: \[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] This shows that 1 mole of zinc reacts with 2 moles of hydrochloric acid. 3. **Determine Moles of HCl Required**: From the balanced equation, we can see that for every 1 mole of zinc consumed, 2 moles of hydrochloric acid are required. 4. **Conclusion**: Therefore, the moles of HCl required to react with 1 mole of zinc is: \[ \text{2 moles of HCl} \] ### Final Answer: 2 moles of HCl are required to react with 1 mole of zinc. ---

To determine the moles of hydrochloric acid (HCl) required to react with 1 mole of zinc (Zn), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction between zinc and hydrochloric acid can be written as: \[ \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 ...
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