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In the reaction N(2)+3H(2) to 2NH(3), th...

In the reaction `N_(2)+3H_(2) to 2NH_(3)`, the volume ratio of the gases as 1: 3: 2 was

A

Boyle

B

Gay-Lussac's law

C

Avogadro

D

Charles

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The correct Answer is:
To solve the question regarding the reaction \( N_2 + 3H_2 \rightarrow 2NH_3 \) and the volume ratio of the gases being 1:3:2, we need to analyze the relationship between the volumes of gases involved in this reaction. ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction given is: \[ N_2 + 3H_2 \rightarrow 2NH_3 \] This is known as Haber’s process for the synthesis of ammonia. 2. **Understand Volume Ratios**: According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain an equal number of molecules. Therefore, the volume ratio of gases in a reaction is directly proportional to the mole ratio of the gases. 3. **Determine the Mole Ratio**: From the balanced equation: - 1 mole of \( N_2 \) - 3 moles of \( H_2 \) - 2 moles of \( NH_3 \) This gives us a mole ratio of: \[ N_2 : H_2 : NH_3 = 1 : 3 : 2 \] 4. **Relate Volume Ratio to Mole Ratio**: Since the volume ratio of the gases is also given as 1:3:2, we can conclude that: \[ \text{Volume ratio} = N_2 : H_2 : NH_3 = 1 : 3 : 2 \] This confirms that the volume ratio matches the mole ratio. 5. **Identify the Relevant Gas Law**: The relationship that connects the volume of gases to the number of moles is described by Avogadro's law, which states that at constant temperature and pressure, the volume of a gas is directly proportional to the number of moles of the gas. 6. **Conclusion**: Therefore, the volume ratio of the gases in the reaction \( N_2 + 3H_2 \rightarrow 2NH_3 \) is expressed by Avogadro's law. ### Final Answer: The volume ratio of the gases \( N_2 : H_2 : NH_3 \) is expressed by **Avogadro's Law**.
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