Home
Class 10
CHEMISTRY
The percentage composition of sodium pho...

The percentage composition of sodium phosphate as determined by analysis is 42.1% sodium, 18.9% phosphorus and 39% oxygen. Find the empirical formula of the compound (work to two decimal places). (R.A.M: Na = 23, P = 31, O = 16.)

Text Solution

AI Generated Solution

To find the empirical formula of sodium phosphate based on the given percentage composition, we can follow these steps: ### Step 1: Convert Percentage to Grams Assume the total mass of the compound is 100 grams. This means: - Sodium (Na): 42.1 g - Phosphorus (P): 18.9 g - Oxygen (O): 39.0 g ...
Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT AND STOICHIOMETRY

    ICSE|Exercise ILLUSTRATIVE ASSIGNMENTS|28 Videos

  • MOLE CONCEPT AND STOICHIOMETRY

    ICSE|Exercise IMPORTANT NUMERICAL EXERCISES|37 Videos

  • MODEL PAPER-2

    ICSE|Exercise SECTION-II|56 Videos

  • MOLE CONCEPT AND STOICHIOMETRY

    ICSE|Exercise ASSERTION AND REASON BASED QUESTIONS|1 Videos

Similar Questions

Explore conceptually related problems

A compound of magnesium contains 21.9% magnesium, 27.8% phosphorus and 50.3% oxygen. What will be the simplest formula of the compound?

A compound X consists of 4.8% carbon and 95.2% bromine by mass. Determine the empirical formula of this compound working correct to one decimal place (C = 12, Br = 80)

Find empirical formula of the compound if M=68% (atomic mass=34) and remaining 32% oxygen.

A substance used as a water softener has the following mass percentage composition : 42.07% Na, 18.9% P , and 39.04% of oxygen. Determine the empirical formula of the compound. (Na = 23, P = 31, 0 = 16)

A compound is composed of 29.11% sodium, 40.51% sulphur and 30.38% oxygen. Find its empirical formula. (R.A.M. : Na = 23, S = 32, O = 16.)

A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correct to 1 decimal place. (H = 1, C = 12, CI = 35.5)

The compound A has 26.7% C, 71.1% O and 2.2%H. determine the empirical formula of A

A compound is composed of 43.4% Na, 11.32% C and rest of oxygen by mass. Derive a empirical formula of the compound. (R.A.M.: C = 12, O = 16, Na - 23)

An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C,38.71% and H,9.67% . The empirical formula of the compound would be :