Compute the moles of `Cl_(2)` produced from `3.2` mol HCl as per equation :
`16HCl + 2KMnO_(4) to 2MnCl_(2) + 2KCl + 8H_(2)O + 5Cl_(2)`

Explanation

Let x be the moles of `Cl_(2)` produced from `3.2` mol HCl.
`underset("16 mol")overset(3.2" mol")(16HCl) + 2KMnO_(4) to 2MnCl_(2) + 2KCl + 8H_(2)O + underset(" 5 mol ") overset(x)(5Cl_(2))`
Ratio proportion : `(3.2 " mol Cl"_(2))/("5 mol"Cl_(2)) `
Or, `x = (3.2 mol HCl xx 5 mol Cl_(2))/(16 mol HCl) = 1 mol Cl_(2)`