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Compute the moles of K(3)PO(4) needed to...

Compute the moles of `K_(3)PO_(4)` needed to produce to produce `0.066` mol KCl as per equation:
`3CaCl_(2) + 2K_(3)PO_(4) to Ca_(3)(PO_(4))_(2) + 6KCl`

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To compute the moles of \( K_3PO_4 \) needed to produce \( 0.066 \) moles of \( KCl \) based on the balanced chemical equation: \[ 3CaCl_2 + 2K_3PO_4 \rightarrow Ca_3(PO_4)_2 + 6KCl \] we can follow these steps: ...
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