Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (`C_3H_8`). (Atomic mass : C = 14, O = 16, H = 1, Molar Volume = 22.4 `dm^3` at S.T.P).

Answer

1

Explanation

`{:(8.8g,,x,,,),(C_(3)H_(8),+,5O_(2)to,3CO_(2),+,4H_(2)O),(44 g,,5xx22.4 L,,,):}`
Ratio proportion : `(8.8 g C_(3)H_(8))/(44 g C_(3)H_(8)) = x/(5 xx 22.4 L) O_(2)`
` :. X = (8.8)/(44) xx 5 xx 22.4 L = 22.4 L `