A 5.0 g sample of `Cu (NO_(3))_(2).n (H_(2)O)` is heated, and 3.9 g of anhydrous salt remains. What is the value of 'n' ?
`Cu(NO_(3))_(2),n(H_(2)O)overset(Delta)toCu(NO_(3))_(2)+nH_(2)O`

Explanation

To solve the problem of finding the value of 'n' in the hydrated copper nitrate `Cu(NO3)2·n(H2O)`, we will follow these steps:

### Step 1: Determine the mass of water lost during heating
We start with the total mass of the hydrated copper nitrate and the mass of the anhydrous copper nitrate remaining after heating.

Given:
- Mass of hydrated copper nitrate = 5.0 g
- Mass of anhydrous copper nitrate = 3.9 g
...