200 g of impure `Na_(2)CO_(3)` of 90% purity is treated with dil. `H_(2)SO_(4)` according to the reaction
`Na_(2)CO_(3)+H_(2)SO_(4)toNa_(2)SO_(4)+H_(2)O+CO_(2)`
Calculate the mass of pure sodium sulphate formed [Na = 23, C = 12, O = 16, H = 1, S = 32]

Explanation

To solve the problem step by step, we will follow the stoichiometry of the reaction and the purity of the sodium carbonate.

### Step 1: Calculate the mass of pure sodium carbonate (Na₂CO₃)
Given that the impure sodium carbonate has a mass of 200 g and a purity of 90%, we can calculate the mass of pure sodium carbonate as follows:

\[ \text{Mass of pure Na}_2\text{CO}_3 = \text{Purity} \times \text{Total mass} = 0.90 \times 200 \, \text{g} = 180 \, \text{g} \]
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