The following experiment was performed in order to qetermine the formula of a hydrocarbon. The hydrocarbon X is purified by fractional distillation. 0.145 g of X were heated with dry copper (II) oxide and `224 cm^(3)` of carbon dioxide was collected at S.T.P
Which elements does X contain ?

The following experiment was performed in order to qetermine the formula of a hydrocarbon. The hydrocarbon X is purified by fractional distillation. 0.145 g of X were heated with dry copper (II) oxide and 224 cm^(3) of carbon dioxide was collected at S.T.P Calculate the empirical formula of X by the following steps : Calculate the number of moles of carbon dioxide gas.

The following experiment was performed in order to qetermine the formula of a hydrocarbon. The hydrocarbon X is purified by fractional distillation. 0.145 g of X were heated with dry copper (II) oxide and 224 cm^(3) of carbon dioxide was collected at S.T.P Calculate the empirical formula of X by the following steps : Calculate the mass of hydrogen in sample X.

The following experiment was performed in order to determine the formula of a hydrocarbon. The hydrocarbon X is purified by fractional distillation. 0.145 g of X were heated with dry copper (II) oxide and 224 cm^(3) of carbon dioxide was collected at S.T.P Calculate the empirical formula of X by the following steps : Deduce the ratio of atoms of each element in X (empirical formula).

Consider the following statements regarding compounds which cause global warming X is a hydrocarbon, A and B are neutral oxides of nitrogen, C is a blue coloured gas and D is released when H_(2)S is reacted with oxygen. Identify the correct statements about X, A , B, C and D. (I) X is mainly present in natural gas (II) In A and B one is diamagnetic and another one is paramagnetic (III) C can be identified by using liquid element in d-block (IV) D causes acid rain

2.24 dm^(3) of dry ammonia gas contain 6 x 10^(22) molecules at S.T .P. Calculate the number of molecules in 56 cm^(3) of dry nitrogen at S.T.P.

The ground state electronic configuration of the elements, U, V, W, X, and Y (these symbols do not have any chemical significance) are as follows: U" "1s^(2)2s^(2)2p^(3) V" "1s^(2)2s^(2)2p^(6)3s^(1) W" "1s^(2)2s^(2)2p^(6)3s^(2)3p^(2) X" "1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(5)4s^(2) Y" "1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^(6) Determine which sequence of elements satisfy the following statements: (i) Element that forms a carbonate which is not decomposed by heating (ii) Element which is most likely to form coloured ionic compound (iii) Element which has largest atomic radius (iv) Element which forms only acidic oxide

The transverse displacement of a string (clamped at its two ends ) is given by y(x,t)=0.06sin((2pi)/(3))xcos(120pit) wherer x ,y are in m and t ini s. The length of the string is 1.5m and its mass is 3xx10^(-2) kg. Answer the following: (i) Does the function represent a travelling or a stationary wave ? (ii) Interpret the wave as a superimposition of two waves travelling in opposite directions. What are the wavelength, frequency and speed of propagation of each wave ? (iii) Determing the tension in the string.

The reaction 2AX(g)+2B_(2)(g)rarr A_(2)(g)+2B_(2)X(g) has been studied kinetically and on the baiss of the rate law following mechanism has been proposed. I. 2A X hArr A_(2)X_(2) " " ("fast and reverse") II. A_(2)X_(2)+B_(2)rarrA_(2)X+B_(2)X III. A_(2)X+B_(2)rarrA_(2)+B_(2)X where all the reaction intermediates are gases under ordinary condition. form the above mechanism in which the steps (elementary) differ conisderably in their rates, the rate law is derived uisng the principle that the slowest step is the rate-determining step (RDS) and the rate of any step varies as the Product of the molar concentrations of each reacting speacting species raised to the power equal to their respective stoichiometric coefficients (law of mass action). If a reacting species is solid or pure liquid, its active mass, i.e., molar concentration is taken to be unity, the standard state. In qrder to find out the final rate law of the reaction, the concentration of any intermediate appearing in the rate law of the RDS is substituted in terms of the concentration of the reactant(s) by means of the law of mass action applied on equilibrium step. Let the equilibrium constant of Step I be 2xx10^(-3) mol^(-1) L and the rate constants for the formation of A_(2)X and A_(2) in Step II and III are 3.0xx10^(-2) mol^(-1) L min^(-1) and 1xx10^(3) mol^(-1) L min^(-1) (all data at 25^(@)C) , then what is the overall rate constant (mol^(-2) L^(2) min^(-1)) of the consumption of B_(2) ?