Calculate the volume of oxygen required for the complete combustion of 20 ml of propane `(C_(3)H_(8))`
`C_(3)H_(8)+5O_(2)to3CO_(2)+4H_(2)O`

Explanation

To calculate the volume of oxygen required for the complete combustion of 20 ml of propane (C₃H₈), we will follow these steps:

### Step 1: Write the balanced chemical equation
The balanced equation for the combustion of propane is:
\[ C_{3}H_{8} + 5O_{2} \rightarrow 3CO_{2} + 4H_{2}O \]

### Step 2: Identify the mole ratio from the balanced equation
From the balanced equation, we can see that 1 mole of propane reacts with 5 moles of oxygen. This means that for every 1 volume of propane, 5 volumes of oxygen are required.
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