Answer
Step by step text solution for prove that "sin"^4pi/8+"sin"^4(3pi)/8+"sin"^4(5pi)/8+"sin"^4 (7pi)/8=3/2 by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.
|
Topper's Solved these Questions
MEASUREMENT OF ANGLES & TRIGONOMETRIC FUNCTIONS
PATHFINDER|Exercise QUESTION BANK|25 VideosView PlaylistPARABOLA, ELLIPSE AND HYPERBOLA
PATHFINDER|Exercise QUESTION BANK|66 VideosView Playlist
Similar Questions
Explore conceptually related problems
Knowledge Check
A
B
C
D
Submit
Similar Questions
Explore conceptually related problems
PATHFINDER-MULTIPLE AND SUB-MULTIPLE ANGLES-QUESTION BANK
- Prove that(1+sintheta-costheta)/(1+sintheta+costheta)="tan"theta/2.
02:27
|
Play - Prove that sqrt(2+sqrt(2+2cos4theta))=2costheta
01:42
|
Play - Find the value of cos^2 48^@-sin^2 12^@
01:49
|
Play - Find the value of sin^2 24^@-sin^2 6^@.
00:56
|
Play - Find the value of "cos"22 1/2@
02:18
|
Play - Prove that 8"cos"^3pi/9-6"cos"pi/9=1
01:33
|
Play - Prove that (sec8theta-1)/(sec4theta-1)=(tan8theta)/(tan2theta)
03:36
|
Play - prove that "sin"^4pi/8+"sin"^4(3pi)/8+"sin"^4(5pi)/8+"sin"^4 (7pi)/8=3...
06:09
|
Playing Now - Prove thatcos^2alpha+cos^2(120^@-alpha)+cos^2(120^@+alpha)=3/2
07:01
|
Play - Prove that "cos" (2pi)/15 cdot "cos"(4pi)/15 cdot "cos" (8pi)/15 "cos...
05:05
|
Play - Prove that cos^3A+cos^3(120^@+A)+cos^3(240^@+A)=3/4cos3A
02:45
|
Play - Prove that tanA+tan(60^@+A)-tan(60^@-A)=3tan3A
05:58
|
Play - Show that cot 7(1^@/2)=2+sqrt2+sqrt3+sqrt6
10:28
|
Play - Prove that tanAcdottan(A+60^@)+tanAcdottan(A-60^@)+tan(A+60^@)tan(A-60...
07:12
|
Play - Prove that abs(sinthetasin(60^@-theta)sin(60^@+theta)) le1/4 for all v...
05:15
|
Play - Prove that if tanA=1/7 and tanB=1/3 then cos2A=sin4B
03:45
|
Play - Prove that tan6^@tan42^@tan66^@tan78^@=1
08:39
|
Play - Prove that (1+"cos" (pi)/10)(1+"cos"(3pi)/10)(1+"cos"(7pi)/10)(1+"cos"...
03:55
|
Play - If sinx=(sqrt5)/3 x lies is the 2nd quadrand then find the value of"c...
04:17
|
Play - Prove that "sin"pi/5"sin"(2pi)/5"sin"(3pi)/5"sin"(4pi)/5=5/(16)
03:05
|
Play