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The straight line x+y+1+ lambda (2x-y-1)...

The straight line `x+y+1+ lambda (2x-y-1)=0` is `bot` to 2x+3y-8=0, find the value of `lambda`.

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Slope of the line
`x+y+1+lambda(2x-y-1)=0` is `-(1+2lambda)/(1-lambda)`
Slope of 2x+3y-8=0 is `-2/3`
`therefore (-1-2lambda)/(1-lambda)xx(-2)/3=-1`
`implies 2+4lambda=-3(1-lambda)=-3+3lambda`
`implies lambda=-5`
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