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If eccentricities of the ellipse x^2/36+...

If eccentricities of the ellipse `x^2/36+y^2/25=1` and `x^2/a^2+y^2/b^2=1 (a^2ltb^2)` be equal, then a:b=

A

4,3

B

9,5

C

3:5

D

5:6

Text Solution

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The correct Answer is:
D
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