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Step by step text solution for If y=tan^(-1)(x^3) then dy/dx= by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.
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PATHFINDER-DERIVATIVES-QUESTION BANK
- If y=tan^(-1)(x^3) then dy/dx=
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- y=1+x+(x^2)/(2!)+(x^3)/(3!)+.....infty ,then dy/dx=
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- f(x)=e^x.g(x),g(0)=2 and g'(0)=1 then f'(0)=
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- y=((x^a)/(x^b))^(a+b).((x^b)/(x^c))^(b+c).((x^c)/(x^a))^(c+a) then dy/...
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- if f(x)=8x^4 then f'(-1/2)=
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- y=e^alogx then dy/dx
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- f(x)=x^2+a then at x=a , f'(x) is
03:33
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- Derivative of sinx^3 with respect to x is
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- y=cos^(-1)x^2 then dy/dx=
02:46
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- d/dx(x^6+6^x)=
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- f(x)=sin^(-1)(2xsqrt(1-x^2)) then f'(x)=
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- y=cos^(-1)x^2 then dy/dx=
02:46
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- if f(x)=x^2-6 then value of f'(6) is
03:01
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- y=sin2x+cos2x what is the value of dy/dx at x=pi/6
03:47
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- x=cos^2(theta)/2 then (dx)/(d theta)
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- y=bsin^-1ax then dy/dx=
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- if f(x)=e^(x)+4x then f'(x)=
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- if y=sin3x then (dy/dx)(x=0) is
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- f(x)=log(x^3) ,f'(x)=?
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- If f(2)=4 ,f'(2)=1, underset(xrarr2)Lt ((xf(2)-2f(x))/(x-2))=?
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