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Solve for 'x' : abs(x-1)+abs(2x-3)=abs...

Solve for 'x' :
`abs(x-1)+abs(2x-3)=abs(3x-4`

Text Solution

Verified by Experts

`(x-1)+(2x-3)=3x-4` by `(absx+absy=abs(x+y)impliesxcdotyge0)`
so, `(x-1)(2x-3)ge0`
`implies x in (- infty,1] cup[3/2,infty)`
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