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If cos (alpha+beta)=4/5 and sin(alpha-be...

If cos `(alpha+beta)=4/5` and `sin(alpha-beta)=5/13` and `alpha,beta` lie between 0 and `pi/4,alphagtbeta`, then, then find `tan 2alpha `

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Here tan `(alpha+beta)=3/4` and tan `(alpha-beta)=5/12` so that tan 2a= tan`{(alpha+beta)+(alpha-beta)}
`=(tan(alpha+beta)+tan(alpha-beta))/(1-tan(alpha+beta)tan(alpha-beta))=(3/4+5/12)/(1-(3/4).5/12)=56/33`
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