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A particle is moving in a vertical line whose equation of motion is given by `s = 32 + 46t+9t^2` where 's' is measured in meters and 't' is measured in seconds. Find the velocity and acceleration of the particle at t=3 sec.

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s = 32+46t-`9t^2`
`implies a=dv/dt=46`
`therefore at t = 3 sec`
velocity (v) = `46 - 18 xx 3 =-8` m/sec and acceleration (a) = 46 `m//sec^2`
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