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Let alpha=pi/3, then the solution set of...

Let `alpha=pi/3`, then the solution set of the inequality `log_(sinalpha)(2-cos^2x)lt log_(sinalpha)(1-sinx)`, where `x in (0,2x)` and `x ne pi/2`, is

A

`(alpha, pi-alpha)`

B

`(alpha, pi/2)cup(pi/2, pi-alpha)`

C

`(pi,3, (5pi)/6)`

D

`(0, pi/2)cup(pi/2, pi)`

Text Solution

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The correct Answer is:
D
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