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If P(x) = ax^2+bx+c, and Q(x) = -ax^2+dx...

If `P(x) = ax^2+bx+c`, and `Q(x) = -ax^2+dx+c, acne `0, then prove that P(x).Q(x) =0 has at least two real roots.

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`D_1` of `P(x) = b^2-4ac
`D_2 of Q(x)=d^2+4ac`
`(D_1+D_2)=b^2+d^2gt0`
Hence at least two roots of P(x) Q(x) = 0 are real.
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